NEETPhysicsMotion in One Dimension
Let us cell a motion, (A ) when velocity is positive and increasing (A⁻¹ ) when velocity is negative and increasing. (R ) when velocity is positive and decreasing and (R⁻¹ ) when velocity is negative and decreasing. Now, match the following two columns for the given (s-t ) graph. ( array |c|l|c|l| & Column I & & Column II (A) & M & (p) & A⁻¹ (B) & N & (q) & R⁻¹ (C) & P & (r) & A (D) & Q & (s) & R array )
Options
- A(( A p , B q , C r , D s ) )
- B(( A q , B p , C r , D s ) )
- C(( A r , B s , C q , D p ) )
- D(( A s , B r , C p , D q ) )
Correct answer
A. (( A p , B q , C r , D s ) )
Step-by-step solution
Rule: velocity (= ) slope of (s-t ) curve (sign from slope), velocity increasing/decreasing (= ) sign of acceleration = concavity of (s(t) ) (concave up ( ) acceleration (>0 ) velocity increasing; concave down ( ) acceleration ( Apply at marked points: - (M ) : slope negative, curve concave up ( ) velocity negative and increasing ( A⁻¹ ). - (N ) : slope negative, curve concave down ( ) velocity negative and decreasing ( R⁻¹ ). - (P ) : slope positive, curve concave up ( ) velocity positive and increasing ( A ). - (