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NEETPhysicsMotion in One Dimension

Match the initial and final directions of a car moving at a constant speed (List-I) with the direction of the average force acting on it during the turn (List-II). List-I List-II (A) Moving North, turns East (I) North-West (B) Moving East, turns South (II) North-East (C) Moving South, turns West (III) South-West (D) Moving West, turns North (IV) South-East Choose the correct answer from the options given below:

Options

  1. A(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
  2. B(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
  3. C(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  4. D(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Correct answer

D. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Step-by-step solution

The direction of the average force is the same as the direction of the change in velocity, v = v _f - v _i . Let the speed be v . We take East as i , North as j , West as - i , and South as - j . (A) Moving North ( v _i = v j ), turns East ( v _f = v i ). v = v i - v j (South-East). So, (A) matches (IV). (B) Moving East ( v _i = v i ), turns South ( v _f = -v j ). v = -v j - v i (South-West). So, (B) matches (III). (C) Moving South ( v _i = -v j ), turns West ( v _f = -v i ). v = -v i - (-v j ) = -v i + v j (North-

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