Two boys are standing at the ends A and B of a ground, where A B=a . The boy at B starts running in a direction perpendicular to A B with velocity v₁ . The boy at A starts running simultaneously with velocity v and catches the other boy in

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Two boys are standing at the ends A and B of a ground, where A B=a . The boy at B starts running in a direction perpendicular to A B with velocity v₁ . The boy at A starts running simultaneously with velocity v and catches the other boy in a time t , where t is

Quantrex Academy · Accepted Answer

Correct answer: B. a^2 v^2-v₁^2

Distance covered by boy A in time tA C=v t (i) Distance covered by boy B in time tB C=v₁ t (ii) Using Pythagoras theorem aligned A C^2 & =A B^2+B C^2 or (v t)^2 & =a^2+ (v₁ t )^2 aligned or v^2 t^2-v₁^2 t^2=a^2 or t^2 (v^2-v₁^2 )=a^2 t= a^2 (v^2-v₁^2 )

Two boys are standing at the ends A and B of a ground, where A B=a . The boy at B starts running in a direction perpendicular to A B with velocity v₁ . The boy at A starts running simultaneously with velocity v and catches the other boy in a time t , where t is

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