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NEET
Exam
NEET
Subject
Physics
Chapter
Rotational Motion

NEET · Physics · Rotational Motion

The moment of inertial of a solid sphere, about an axis parallel to...

The moment of inertial of a solid sphere, about an axis parallel to its diameter and at a distance of xx from it, is ′I(x)′.′I{\left(x\right)}^{′} . Which one of the graphs represents the variation of I(x)I ( x ) with xx correctly?The moment of inertial of a solid sphere, about an axis parallel to its diameter and at a distance of x from it, is ′IThe moment of inertial of a solid sphere, about an axis parallel to its diameter and at a distance of x from it, is ′IThe moment of inertial of a solid sphere, about an axis parallel to its diameter and at a distance of x from it, is ′IThe moment of inertial of a solid sphere, about an axis parallel to its diameter and at a distance of x from it, is ′I

Options

  1. AThe number of time(s) decarboxylation of isocitrate occurs during single TCA cycle is :
  2. BThe number of time(s) decarboxylation of isocitrate occurs during single TCA cycle is :
  3. CThe number of time(s) decarboxylation of isocitrate occurs during single TCA cycle is :
  4. DThe number of time(s) decarboxylation of isocitrate occurs during single TCA cycle is :

Correct answer

A. The number of time(s) decarboxylation of isocitrate occurs during single TCA cycle is :

Step-by-step solution

we know that by se the parallel axis theorem :-

Moment of inertia about a point which is parallel of the axis and at a distance of  X given as 

Ix=Icm+mx2{I}_{x} = {I}_{cm} + m{x}^{2}

Ix=25mR2+mx2⇒{I}_{x} = \dfrac{2}{5}m{R}^{2} + m{x}^{2} ⇒ Parabola opening upward

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