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NEET
Exam
NEET
Subject
Physics
Chapter
Rotational Motion

NEET · Physics · Rotational Motion

A particle of mass ( m ) is projected at a velocity ( u ), making...

A particle of mass (m\mathrm{m}) is projected at a velocity (u\mathrm{u}), making an angle (θ\theta) with the horizontal ( (x\mathrm{x})-axis). If the angle of projection (θ\theta) is varied keeping all other parameters same, then magnitude of angular momentum (L) at its maximum height about the point of projection varies with (θ\theta) as,A particle of mass ( m ) is projected at a velocity ( u ), making an angle ( θ ) with the horizontal ( ( x )-axis). IfA particle of mass ( m ) is projected at a velocity ( u ), making an angle ( θ ) with the horizontal ( ( x )-axis). IfA particle of mass ( m ) is projected at a velocity ( u ), making an angle ( θ ) with the horizontal ( ( x )-axis). IfA particle of mass ( m ) is projected at a velocity ( u ), making an angle ( θ ) with the horizontal ( ( x )-axis). IfA particle of mass ( m ) is projected at a velocity ( u ), making an angle ( θ ) with the horizontal ( ( x )-axis). If

Options

  1. ADuring the beginning of ventricular diastole, as the ventricular pressure declines, a distinct acoustic event is
  2. BDuring the beginning of ventricular diastole, as the ventricular pressure declines, a distinct acoustic event is
  3. CDuring the beginning of ventricular diastole, as the ventricular pressure declines, a distinct acoustic event is
  4. DDuring the beginning of ventricular diastole, as the ventricular pressure declines, a distinct acoustic event is

Correct answer

D. During the beginning of ventricular diastole, as the ventricular pressure declines, a distinct acoustic event is

Step-by-step solution

Hint : A particle of mass ( m ) is projected at a velocity ( u ), making an angle ( θ ) with the horizontal ( ( x )-axis). If
L0=mucos⁡θH=mucos⁡θu2sin⁡2θ2 g=mu3sin⁡2θcos⁡θ2 g\begin{aligned} & \mathrm{L}_0=m u \cos \theta \mathrm{H} \\ & =m u \cos \theta \frac{\mathrm{u}^2 \sin ^2 \theta}{2 \mathrm{~g}} \\ & =\frac{m u^3 \sin ^2 \theta \cos \theta}{2 \mathrm{~g}} \end{aligned}) LL is zeroforfor(\theta=0^{\circ}) and (\theta=\frac{\pi}{2})$
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