NEETPhysicsRotational Motion
Match List-I with List-II regarding the angular momentum of various rigid bodies. Let L_C be the magnitude of angular momentum of the body about its centre of mass and L_P be the magnitude of its angular momentum about a stationary point on the ground. List-I (Object and its motion) List-II (Relation) A. A disc rotating about a fixed vertical axis passing through its centre of mass I. L_P = 3 L_C B. A uniform ring ro
Options
- AA-II, B-I, C-IV, D-III
- BA-II, B-IV, C-I, D-III
- CA-I, B-IV, C-II, D-III
- DA-IV, B-II, C-III, D-I
Correct answer
B. A-II, B-IV, C-I, D-III
Step-by-step solution
The angular momentum about a point P on the ground is L _P = L _C + r _ cm M v _ cm . For a body rotating about a fixed axis through its centre of mass, v _ cm = 0 . Hence, L_P = L_C . This matches A with II. For a body rolling without slipping on a horizontal surface, v_ cm = R . Both spin and orbital angular momentum are in the same direction. L_P = I_ cm + Mv_ cm R = I_ cm ( v_ cm R ) + Mv_ cm R For a ring, I_ cm = MR^2 , so L_C = Mv_ cm R . L_P = Mv_ cm R + Mv_ cm R = 2Mv_ cm R = 2L_C . This matches B with IV.