NEET2017PhysicsRotational MotionActual
A communication satellite of 500 ~kg revolves around the earth in a circular orbit of radius 4.0 10^7 ~m in the equatorial plane of the earth from west to east. The magnitude of angular momentum of the satellite is
Options
- A0.13 10¹⁴ ~kg ~m ^2 ~s ⁻¹
- B1.3 10¹⁴ ~kg ~m ^2 ~s ⁻¹
- C0.58 10¹⁴ ~kg ~m ^2 ~s ⁻¹
- D2.58 10¹⁴ ~kg ~m ^2 ~s ⁻¹
Correct answer
C. 0.58 10¹⁴ ~kg ~m ^2 ~s ⁻¹
Step-by-step solution
As the satellite is moving in equatorial plane with orbital radius 4 10^7 ~m . Satellite is geostationary satellite. Hence, the time taken by satellite to complete its one revolution, T=24 ~h =86400 ~s Velocity of satellite, v= 2 r T Angular momentum, L=m v r aligned & L=m ( 2 r T ) r= 2 m T r^2 & L= 2 3.14 500 86400 (4 10^7 )^2 & =0.58 10¹⁴ ~kg ~m ^2 ~s ⁻¹ & aligned