NEET2007PhysicsRotational MotionActual
If a solid sphere of mass (1 ~kg ) and radius (0.1 ~m ) rolls without slipping at a uniform velocity of (1 ~m / s ) along a straight line on a horizontal floor, the kinetic energy is
Options
- A( 7 5 ~J )
- B( 2 5 ~J )
- C( 7 10 ~J )
- D(1 ~J )
Correct answer
C. ( 7 10 ~J )
Step-by-step solution
( gathered K . E of rolling = ( 1 2 m v^2+ 1 2 I v^2 R^2 ) K E = 1 2 m v^2+ 1 2 2 5 m R^2 v^2 R^2 ~K . E = 1 2 m v^2 7 5 m=1 ~kg , v = 1 ~m/s ~K E = 1 2 1 1 7 5 = 7 10 ~J gathered )