The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is

Step-by-step solution

We should use parallel axis theorem. Moment of inertia of disc passing through its centre of gravity and perpendicular to its plane is I_ A B = 1 2 M R^2 Using theorem of parallel axes, we have aligned I_ C D & =I_ A B +M R^2 & = 1 2 M R^2+M R^2 & = 3 2 M R^2 aligned NOTE : The role of moment of inertia in the study of rotational motion is analogous to that of mass in study of linear motion.