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Exam
NEET
Subject
Physics
Chapter
Gravitation

NEET · Physics · Gravitation

The graph correctly represents the variation of acceleration due to...

The graph correctly represents the variation of acceleration due to gravity (g)(g) with radial distance from the centre of the earth (radius of the earth =Re=R_e ) isThe graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre ofThe graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre ofThe graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre ofThe graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre ofThe graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre ofThe graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre of

Options

  1. AA straight magnetic strip has a magnetic moment of 44 Am^2 . If the strip is bent in a semicircular shape, its magnetic
  2. BA straight magnetic strip has a magnetic moment of 44 Am^2 . If the strip is bent in a semicircular shape, its magnetic
  3. CA straight magnetic strip has a magnetic moment of 44 Am^2 . If the strip is bent in a semicircular shape, its magnetic
  4. DA straight magnetic strip has a magnetic moment of 44 Am^2 . If the strip is bent in a semicircular shape, its magnetic

Correct answer

B. A straight magnetic strip has a magnetic moment of 44 Am^2 . If the strip is bent in a semicircular shape, its magnetic

Step-by-step solution

At depth dd, g′=g(1−dRe)=g(Re−dRe)=grReg^{\prime}=g\left(1-\frac{d}{R_e}\right)=g\left(\frac{R_e-d}{R_e}\right)=\frac{g r}{R_e} ⇒g′∝r(\Rightarrow g^{\prime} \propto r( where, r=r= distance from centre of earth )) The graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre of
At height hh, g′=g(Re2(Re+h)2)=gRe2r2⇒g′∝1r2g^{\prime}=g\left(\frac{R_e^2}{\left(R_e+h\right)^2}\right)=\frac{g R_e^2}{r^2} \Rightarrow g^{\prime} \propto \frac{1}{r^2} So, correct graph isThe graph correctly represents the variation of acceleration due to gravity (g) with radial distance from the centre of
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