A tank contains three immiscible liquids stacked on top of each other. The layers consist of water (density 1 g cm^ -3 ), an oil (density 0.8 g cm^ -3 ), and mercury (density 13.6 g cm^ -3 ), each having a column height

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Quantrex Academy · Accepted Answer

Correct answer: D. 154 cm

The total hydrostatic pressure at the bottom of the tank is the sum of the pressures exerted by each liquid layer.

P_{\text{total}} = \rho_{\text{water}} g h + \rho_{\text{oil}} g h + \rho_{\text{mercury}} g h

P_{\text{total}} = (1 + 0.8 + 13.6) \times g \times 10

P_{\text{total}} = 15.4 \times 10 \times g = 154 g

For an equivalent pure water column of height

H_{\text{equiv}}

:

P_{\text{water}} = \rho_{\text{water}} g H_{\text{equiv}} = 1 \times g \times H_{\text{equiv}}

Equating the pressures:

1 \times g \times H_{\text{equiv}} = 154 g

H_{\text{equiv}} = 154\text{ cm}

Answer:

154\text{ cm}

A tank contains three immiscible liquids stacked on top of each...

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