Two identical beakers A and B contain equal volumes of two different liquids at 60 ° C each and left to cool down. Liquid in A has density of 8 × 10 ^ 2 kg m ^ - 3 and specific heat of 2000Jk g ^ - 1 K ^ - 1 while the

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Correct answer: B.

From Newton's law of cooling,
Rate of cooling:

\left(- \dfrac{dT}{dt}\right) = \dfrac{4\sigmaeA{T}_{0}^{3}\left(T - {T}_{0}\right)}{ms}∝ \dfrac{1}{ms}

∴ {ρ}_{A} < {ρ}_{B}

{m}_{A} < {m}_{B}

And

{s}_{A} < {s}_{B}

{m}_{A}{s}_{A} < {m}_{B}{s}_{B}

At

t = 0, {\left(- \dfrac{dT}{dt}\right)}_{A} > {\left(- \dfrac{dT}{dt}\right)}_{B}

Initially, the rate of cooling for

A

will be higher than

B

and temperature

( T )

vs time

( t )

graph will be a curve.

Two identical beakers A and B contain equal volumes of two...

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