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AIIMS 2017
Exam
AIIMS
Year
2017
Subject
Physics
Chapter
Thermal Properties of Matter

AIIMS 2017 · Physics · Thermal Properties of Matter

A body initially at 80^ C cools to 64^ C in 5 ~min and to 52^ C in...

A body initially at 80∘C80^{\circ} \mathrm{C} cools to 64∘C64^{\circ} \mathrm{C} in 5 min5 \mathrm{~min} and to 52∘C52^{\circ} \mathrm{C} in 10 min10 \mathrm{~min}. The temperature of the surrounding is

Options

  1. A26∘C26^{\circ} \mathrm{C}
  2. B16∘C16^{\circ} \mathrm{C}
  3. C36∘C36^{\circ} \mathrm{C}
  4. D40∘C40^{\circ} \mathrm{C}

Correct answer

B. 16∘C16^{\circ} \mathrm{C}

Step-by-step solution

According to Newton's law of cooling θ1−θ2t=K\frac{\theta_1-\theta_2}{t}=K\left[\frac{\theta_1+\theta_2}{2}-\theta_0\right]Inthefirstcase,In the first case,\frac{80-64}{5}=K[80+642−θ0]\left[\frac{80+64}{2}-\theta_0\right] or 3.2=K\quad 3.2=K\left[72-\theta_0\right]Inthesecondcase,In the second case,\frac{64-52}{5}=K[64+522−θ0]\left[\frac{64+52}{2}-\theta_0\right] or 2.4=K\quad 2.4=K\left[58-\theta_0\right]Dividing(i)by(ii),wegetDividing (i) by (ii), we get\frac{3.2}{2.4}=\frac{72-\theta_0}{58-\theta_0}oror\quad 185.6-3.2 \theta_0=172.8-2.4 \theta_0oror\theta_0=16^{\circ} \mathrm{C}
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