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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Physics
Chapter
Thermal Properties of Matter

JIPMER 2016 · Physics · Thermal Properties of Matter

A system consist of a cylinder surrounded by a cylindrical shell. A...

A system consist of a cylinder surrounded by a cylindrical shell. A cylinder is a radius RR and is made of material of thermal conductivity KK, whereas a cylindrical shell has inner radius RR and outer radius 2R2 R and is made of material of thermal conductivity twice as that of cylinder. Assuming the system in steady state and negligible heat loss across the cylindrical surface, find the effective thermal conductivity of the system, if the two ends of the combined system are maintained at two different temperatures.

Options

  1. A3K3 K
  2. B23K\frac{2}{3} K
  3. C7K4\frac{7 K}{4}
  4. D5K4\frac{5 K}{4}

Correct answer

C. 7K4\frac{7 K}{4}

Step-by-step solution

∴R1=LK1⋅πR2\therefore \quad R_1=\frac{L}{K_1 \cdot \pi R^2} and R2=LK2(4πR2−πR2)=L3K2πR2Req =LKeq ⋅4πR2\begin{aligned} R_2 & =\frac{L}{K_2\left(4 \pi R^2-\pi R^2\right)}=\frac{L}{3 K_2 \pi R^2} \\ R_{\text{eq }} & =\frac{L}{K_{\text{eq }} \cdot 4 \pi R^2}\end{aligned}R_1 and R_2areinparallel.are in parallel.\therefore \quad \frac{1}{R_{\text{eq }}}=\frac{1}{R_1}+\frac{1}{R_2} ⇒4πR2Keq L=πR2K1L+3πR2K2L⇒4Keq =K1+3K2\begin{aligned} \Rightarrow & & \frac{4 \pi R^2 K_{\text{eq }}}{L} & =\frac{\pi R^2 K_1}{L}+\frac{3 \pi R^2 K_2}{L} \\ & \Rightarrow & 4 K_{\text{eq }} & =K_1+3 K_2\end{aligned}OnputtingvaluesofOn putting values ofK_1 and K_2,weget, we get4Keq =K+3(2K)[∵K1=K,K2=2K]Keq =K+6K4=7K4\begin{aligned} 4 K_{\text{eq }} & =K+3(2 K) \quad\left[\because K_1=K, K_2=2 K\right] \\ K_{\text{eq }} & =\frac{K+6 K}{4}=\frac{7 K}{4}\end{aligned}$
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