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NEET
Exam
NEET
Subject
Physics
Chapter
Thermodynamics

NEET · Physics · Thermodynamics

Figure below shows two paths that may be taken by a gas to go from...

Figure below shows two paths that may be taken by a gas to go from a state AA to a state (c)(c)
Figure below shows two paths that may be taken by a gas to go from a state A to a state (c) In process AB, 400 ~J of
In process AB,400 J\mathrm{AB}, 400 \mathrm{~J} of heat is added to the system and in process BC,100 J\mathrm{BC}, 100 \mathrm{~J} of heat is added to the system. The heat absorbed by the system in the process AC will be

Options

  1. A500 J500 \mathrm{~J}
  2. B460 J460 \mathrm{~J}
  3. C300 J300 \mathrm{~J}
  4. D380 J380 \mathrm{~J}

Correct answer

B. 460 J460 \mathrm{~J}

Step-by-step solution

In cyclic process ABCA Qcycle =Wcycl \mathrm{Q}_{\text{cycle }}=\mathrm{W}_{\text{cycl }}
QAB+QBC+QCA=\mathrm{Q}_{\mathrm{AB}}+\mathrm{Q}_{\mathrm{BC}}+\mathrm{Q}_{\mathrm{CA}}= ar. of ΔABC\Delta \mathrm{ABC}
+400+100+QC→A=12(2×10−3)(4×104)+400+100+\mathrm{Q}_{\mathrm{C} \rightarrow \mathrm{A}}=\frac{1}{2}\left(2 \times 10^{-3}\right)\left(4 \times 10^{4}\right)
⇒QC→A=−460 J\Rightarrow \mathrm{Q}_{\mathrm{C} \rightarrow \mathrm{A}}=-460 \mathrm{~J}
⇒QA→C=+460 J\Rightarrow \mathrm{Q}_{\mathrm{A} \rightarrow C}=+460 \mathrm{~J}
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