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NEET
Exam
NEET
Subject
Physics
Chapter
Thermodynamics

NEET · Physics · Thermodynamics

Helium gas goes through a cycle ABCDA (consisting of two isochoric...

Helium gas goes through a cycle ABCDAABCDA (consisting of two isochoric and two isobaric lines) as shown in figure. The efficiency of this cycle is approximately

Helium gas goes through a cycle ABCDA (consisting of two isochoric and two isobaric lines) as shown in figure. The

Options

  1. A15.415 . 4 %
  2. B9.19 . 1 %
  3. C10.510 . 5 %
  4. D12.512 . 5 %

Correct answer

A. 15.415 . 4 %

Step-by-step solution

Helium is mono atomic gas, for which
CV=32R.Cp=52R{C}_{V} = \dfrac{3}{2}R . {C}_{p} = \dfrac{5}{2}R

Work done by the gas in one complete cycle W=W = area ABCDA=p0V0ABCDA = {p}_{0}{V}_{0}

From AA to BB, Heat given to gas =nCV\DeltaT= n{C}_{V}\DeltaT

=1×(32R)×\DeltaT=32V0(\Deltap)=32V0p0= 1 \times \left(\dfrac{3}{2}R\right) \times \DeltaT = \dfrac{3}{2}{V}_{0}\left(\Deltap\right) = \dfrac{3}{2}{V}_{0}{p}_{0}

From BB to CC, heat given to gas =nCp\DeltaT= n{C}_{p}\DeltaT

=1×(52R)×\DeltaT=52(2p0)\DeltaV=5p0V0= 1 \times \left(\dfrac{5}{2}R\right) \times \DeltaT = \dfrac{5}{2}\left(2{p}_{0}\right)\DeltaV = 5{p}_{0}{V}_{0}

Efficiency of cycle =Workdonebythegas/cycleTotalheatgiventogas/cycle= \dfrac{Workdonebythegas / cycle}{Totalheatgiventogas / cycle}

=p0V032p0V0+5p0V0=213= \dfrac{{p}_{0}{V}_{0}}{\dfrac{3}{2}{p}_{0}{V}_{0} + 5{p}_{0}{V}_{0}} = \dfrac{2}{13}

Efficiency \left(%\right) = \dfrac{2}{13} \times 100 = 15 . 4 %

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