NEET
- Exam
- NEET
- Subject
- Physics
- Chapter
- Thermodynamics
NEET · Physics · Thermodynamics
Match the following List - I amp; List - II i) Isothermal process...
Match the following
The correct answer is
| List - I | amp; List - II |
| i) Isothermal process | amp; a) 0 |
| ii) Isobaric process | amp; b) \frac{1}{\gamma-1}\left[P_2 V_2-P_1 V_1\right] |
| iii) Isochoric process | amp; c) \mu RT \ln |
| iv) Adiabatic process | amp; d) P \left(V_2-V_1\right) |
Options
- Ai-c, ii-d, iii-a, iv-b
- Bi-a, ii-d, iii-b, iv-c
- Ci-c, ii-b, iii-d, iv-a
- Di-b, ii-c, iii-a, iv-d
Correct answer
A. i-c, ii-d, iii-a, iv-b
Step-by-step solution
Work done in any quasi-static process (=W=\int_{V_1}^{V_2} P d V). Evaluate this for each process.
i) Isothermal process (( constant).
Use ideal gas: (constant (T \Rightarrow n R T=) constant).
(W=\int_{V_1}^{V_2} P d V=\int_{V_1}^{V_2} d V=n R T \ln
So isothermal (\Rightarrow) match (c).
ii) Isobaric process (( constant).
If pressure is constant,
(W=\int_{V_1}^{V_2} P d V=P\mathrm{V}=d V=0 For adiabatic reversible: (P V^\gamma=constant. Let (P V^\gamma=\frac{K}{1-\gamma}\left(V_2^{1-}-V_1^{1-}\right))
Using (K=P_1 V_1^P_2 V_2^ and simplifying gives the standard form
(W=
So adiabatic (\Rightarrow) match (b).
Final matching:
i - c, ii , iii , iv .