NEET
- Exam
- NEET
- Subject
- Physics
- Chapter
- Thermodynamics
NEET · Physics · Thermodynamics
Match of the following. Column I Column II array ll A. Ratio of (Δ...
Match of the following.
$$
$$
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
We know that, at constant volume, Heat supplied,
At constant pressure, heat supplied,
Ratio of heat capacity at constant pressure to constant volume is
Now,
Now, \begin{aligned}
\beta & =\frac{Q_2}{W}=\frac{\text{ Heat absorbed from food stuff }}{\text{ Electrical work done }} \\
\therefore \quad \beta & =\frac{Q_2}{Q_1-Q_2}
\end{aligned}$=\frac{\text{ Heat released }}{\text{ Electrical work }}\quad \alpha=\frac{Q_1}{W}=\frac{Q_1}{Q_1-Q_2}\frac{Q_1}{Q_2}=\frac{T_1}{T_2}\beta=\frac{Q_2}{Q_1-Q_2}=\frac{\frac{Q_2}{Q_1}}{1-\frac{Q_2}{Q_1}} =\frac{\frac{T_2}{T_1}}{1-\frac{T_2}{T_1}}=\frac{T_2}{T_1-T_2}\alpha=\frac{Q_1}{Q_1-Q_2} =\frac{\frac{Q_1}{Q_2}}{\frac{Q_1}{Q_2}-1}=\frac{\frac{T_1}{T_2}}{\frac{T_1}{T_2}-1} =\frac{T_1}{T_1-T_2}\mathrm{A} \rightarrow 4, \mathrm{ B} \rightarrow 3, \mathrm{C} \rightarrow 2\mathrm{D} \rightarrow 1$.