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NEET2017PhysicsKinetic Theory of GasesActual

Two identical glass spheres filled with air are connected by a horizontal glass tube. The glass tube contains a pellet of mercury at its mid-point. Air in one sphere is at 0^ C and the other is at 20^ C . If both the vessels are heated through 10^ C , then neglecting the expansions of the bulbs and the tube

Options

  1. Athe mercury pellet gets displaced towards the sphere at lower temperature.
  2. Bthe mercury pellet gets displaced towards the sphere at higher temperature.
  3. Cthe mercury pellet does not get displaced at all.
  4. Dthe temperature rise causes the pellet to expand without any displacement.

Correct answer

C. the mercury pellet does not get displaced at all.

Step-by-step solution

Let n₁ and n₂ be the number of moles in the bulbs at 0^ C and 20^ C , respectively. Then, p V=273 n₁ R=293 n₂ R n₁ n₂ = 293 273 ...(i) When the vessels are heated, let the volume of low temperature be V₁ and that of the other be V₂ . Since, pressure are same, hence V₁ p=283 n₁ R and V₂ p=303 n₂ R V₁ V₂ = 283 n₁ 303 n₂ ...(ii) From Eqs. (i) and (ii), we get V₁ V₂ = 283 303 293 273 =1 Thus, the mercury pellet remains at the same position.

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