A graph between pressure P (along y -axis) and absolute...

A graph between pressure

P

(along

y

-axis) and absolute temperature,

T

(along

x

-axis) for equal moles of two gases has been drawn. Given that volume of second gas is more than volume of first gas. Which of the following statement is correct?

Options

ASlope of gas 1 is less than gas 2
BSlope of gas 1 is more than gas 2
CBoth have some slopes
DNone of the above

Correct answer

B. Slope of gas 1 is more than gas 2

Step-by-step solution

According to ideal gas equation, p V=n R T or

\frac{p}{T}=\frac{n R}{V}, \frac{p}{T}

represents slope of the graph As the number of moles are the same for the two gases,

\begin{aligned} & \therefore \quad \frac{p}{T} \propto \frac{1}{V} \\ & \because \quad V_2 > V_1 \text{ (Given) } \\ & \therefore \quad(\text{ Slope })_2 < (\text{ Slope })_1 \\ & \text{ or } \quad(\text{ Slope })_1 > (\text{ Slope })_2 \\ & \end{aligned}

Practice Kinetic Theory of Gases on Quantrex Academy →

More from Kinetic Theory of Gases