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A simple pendulum is suspended from the celling of a lift. Three cases of lift are given In which case time period of pendulum is ( T =2 ~g )

Options

  1. Aonly in (a)
  2. Bonly in (b)
  3. Conly in (c)
  4. Din both (a) & (b)

Correct answer

D. in both (a) & (b)

Step-by-step solution

(a) Lift is at rest ( a =0 ) (b) lift is moving downward with constant speed ( ) constant velocity ( a =0 ) in both cases ( a =0 ) so ( g _ eff = g ) ( T =2 ~g ) (c) In this case lift is moving with increasing speed so acceleration is downward. ( g _ eff = g - a )

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