When a body is in SHM , then match the following. List - I List -...

In $S . H . M .$
If equation of $S . H . M .$ is given by$y = Asin\omegat$
Velocity $v = \omega\sqrt{{A}^{2} - {x}^{2}}$
And Acceleration $a = - {\omega}^{2}x$
Here $\omega$ is angular frequency and $x$ is displacement from mean position.

From velocity equation we can see that velocity will be max when $x = 0$ i.e. particle is at mean position.

From acceleration equation we can see that acceleration is maximum at when particle is at extreme position i.e. $x = A$.
Kinetic energy is $\dfrac{1}{2}m{v}^{2} = \dfrac{m{\omega}^{2}}{2}\left({A}^{2} - {x}^{2}\right)$
Hence, Kinetic energy will be $\dfrac{3}{4}th$ of maximum kinetic energy$\dfrac{1}{2}m{\omega}^{2}{A}^{2}$ when displacement is equal to half of amplitude\left(A\right) .$</p><p>Potential energy is given by$\dfrac{1}{2}m{\omega}^{2}{x}^{2}$. <br />Hence potential energy will be$\dfrac{3}{4}th$of the maximum potential energy\left(\dfrac{1}{2}m{\omega}^{2}{A}^{2}\right)$ , when displacement from mean position is equal to $\dfrac{\sqrt{3}}{2}A .$