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A block attached to an ideal spring is oscillating on a smooth horizontal surface, executing simple harmonic motion. What is the phase difference between the restoring force exerted by the spring and the velocity of the block?

Options

  1. AZero
  2. B2 rad
  3. Crad
  4. D4 rad

Correct answer

B. 2 rad

Step-by-step solution

In simple harmonic motion, the displacement of the block can be represented as x = A ( t) . The velocity of the block is the rate of change of displacement: v = dx dt = A ( t) = A ( t + 2 ) The restoring force exerted by the spring is directly proportional to the negative of displacement (Hooke's Law): F = -kx = -kA ( t) = kA ( t + ) Comparing the phase angles, the phase of velocity is ( t + 2 ) and the phase of the restoring force is ( t + ) . The phase difference between the restoring force and the velocity is: =

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