In a simple harmonic motion, which of the following pairs of physical quantities exhibits a constant phase difference of 2 radians?

Step-by-step solution

For a particle executing simple harmonic motion, let the displacement be given by x = A ( t) . The velocity is the first derivative of displacement: v = dx dt = A ( t) = A ( t + 2 ) The acceleration is the first derivative of velocity: a = dv dt = -A ^2 ( t) = A ^2 ( t + ) Comparing the phase angles: The phase difference between displacement and velocity is 2 . The phase difference between velocity and acceleration is - 2 = 2 . The phase difference between displacement and acceleration is . Since restoring force is