NEET2002PhysicsOscillationsActual
Displacement between the maximum potential energy (P.E.) position and the maximum energy (K.E.) position for a particle executing simple harmonic motion is:
Options
- Aa 2
- Ba
- C2 a
- D- 1
Correct answer
B. a
Step-by-step solution
The K.E. of pendulum aligned & = K . E . & = 1 2 K (a^2-y^2 ) aligned and P.E. of pendulum = 1 2 K Y^2 when y=0 (mean position) K.E. is maximum and PE is 0 . When y=0 , K.E. is 0 and P.E. is maximum. The displacement between position of maximum potential energy and maximum kinetic energy is a .