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NEET2016PhysicsOscillationsActual

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T . If the mass is increased by m , then the time period becomes ( 5 4 T ) . The ratio of m M is

Options

  1. A9 / 16
  2. B5 / 4
  3. C25 / 16
  4. D4 / 5

Correct answer

A. 9 / 16

Step-by-step solution

T=2 M K and T₁=2 M+m K or T₁ T = M+m M or 5 4 = (1+ m M )^ 1 2 or m M = 25 16 -1= 9 16 ( T₁= 5 4 T )

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