Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEET2014PhysicsOscillationsActual

The time period of a particle undergoing SHM is 16 ~s . It starts motion from the mean position. After 2 ~s , its velocity is 0.4 ~m ~s ⁻¹ . The amplitude is

Options

  1. A1.44 ~m
  2. B0.72 ~m
  3. C2.88 ~m
  4. D0.36 ~m

Correct answer

A. 1.44 ~m

Step-by-step solution

Velocity, v=r t0.4=r 2 16 2 16 2=r 2 16 1 2 or r= 0.4 16 2 2 = 3.2 2 =1.44 ~m

Practice Oscillations on Quantrex Academy →

More from Oscillations

A simple pendulum oscillating in air has a period of 3 second. If it is immersed in a non-viscous liquid, having density = ( 1 x ) , where is the density of the material of the bob 2026Identify the equation that DOES NOT represent oscillatory motion. ( A is amplitude of motion) 2026The potential energy of a simple harmonic oscillator when the particle is at 3 4 A , is ( A is the amplitude of oscillation and E is the total energy of the oscillator) 2026Two SHM's x₁ = a ( t + 3 2 ) and x₂ = a ( t + ) are superimposed on each other. The resultant amplitude of motion is ( /2 = 1 and /2 = 0) 2026The average acceleration of a particle performing S.H.M. over two complete oscillations is (A = amplitude, = angular frequency) 2026The periodic time of a simple pendulum, (the simple pendulum with its bob is in air) is T. But if the bob of the simple pendulum is completely immersed in a non viscous liquid, who 2026The graph shows variation of displacement of a particle performing SHM with time t. which of the following statements is correct from the graph? 2026Two particles A and B execute S.H.M.s of periods T and 5T 2 . If they start from the mean position, then the phase difference between them when the particle A completes two oscilla 2026 Full Oscillations list All NEET PYQs