NEET2013PhysicsOscillationsActual
A simple pendulum performs simple harmonic motion about x=0 with an amplitude ' a ' and time period ' T '. The speed of the pendulum at x=a / 2 will be
Options
- Aa T
- B3 ^2 a T
- Ca 3 T
- Da 3 2 T
Correct answer
C. a 3 T
Step-by-step solution
As simple pendulum performs simple harmonic motion. velocity, v= a^2-x^2 At, x= a 2 v= 2 T a^2- ( a 2 )^2 = 2 T 3 a^2 2 = a 3 T