NEET2018PhysicsOscillationsActual
A particle doing SHM having amplitude 5 cm , mass 0.5 kg and angular frequency 5 rad / s is at 1 cm from mean position. Find potential energy and kinetic energy.
Options
- AKE =6.25 10⁻⁴ ~J , PE =150 10⁻³ ~J
- BKE =150 10⁻⁴ ~J , PE =6.25 10⁻⁴ ~J
- CKE =6.25 10⁻⁴ ~J , PE =6.25 10⁻⁴ ~J
- DKE =150 10⁻³ ~J , PE =150 10⁻⁴ ~J
Correct answer
B. KE =150 10⁻⁴ ~J , PE =6.25 10⁻⁴ ~J
Step-by-step solution
Given, m =0.5 ~kg . =5 rad / s , x =10⁻² ~m , A =5 10⁻² ~m Potential energy, U = 1 2 ~m ^2 x ^2 or U = 1 2 0.5 (5)^2 (10⁻² )^2= 25 4 10⁻⁴ ~J =6.25 10⁻⁴ ~J Kinetic energy, K = 1 2 ~m ^2 ( ~A ^2- x ^2 ) or K = 1 2 0.5 (5)^2(25-1) 10⁻⁴=150 10⁻⁴ ~J