Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEET2014PhysicsOscillationsActual

A mass of 1 kg is suspended from a spring of force constant 400 N , executing SHM total energy of the body is 2 J , then maximum acceleration of the spring will be

Options

  1. A4 ~m / s ^2
  2. B40 ~m / s ^2
  3. C200 ~m / s ^2
  4. D400 ~m / s ^2

Correct answer

B. 40 ~m / s ^2

Step-by-step solution

T=2 m R =2 1 400 = 2 20 Frequency n= 20 2 =2 n=2 20 2 =20 Total energy aligned & E= 1 2 m ^2 r^2 & 2= 1 2 1 400 r^2 aligned gathered r= 1 10 ~m Acceleration = ^2 r=400 1 10 =40 ~m / s ^2 gathered

Practice Oscillations on Quantrex Academy →

More from Oscillations

A simple pendulum oscillating in air has a period of 3 second. If it is immersed in a non-viscous liquid, having density = ( 1 x ) , where is the density of the material of the bob 2026Identify the equation that DOES NOT represent oscillatory motion. ( A is amplitude of motion) 2026The potential energy of a simple harmonic oscillator when the particle is at 3 4 A , is ( A is the amplitude of oscillation and E is the total energy of the oscillator) 2026Two SHM's x₁ = a ( t + 3 2 ) and x₂ = a ( t + ) are superimposed on each other. The resultant amplitude of motion is ( /2 = 1 and /2 = 0) 2026The average acceleration of a particle performing S.H.M. over two complete oscillations is (A = amplitude, = angular frequency) 2026The periodic time of a simple pendulum, (the simple pendulum with its bob is in air) is T. But if the bob of the simple pendulum is completely immersed in a non viscous liquid, who 2026The graph shows variation of displacement of a particle performing SHM with time t. which of the following statements is correct from the graph? 2026Two particles A and B execute S.H.M.s of periods T and 5T 2 . If they start from the mean position, then the phase difference between them when the particle A completes two oscilla 2026 Full Oscillations list All NEET PYQs