NEET2004PhysicsOscillationsActual
The spring extends by x on loading, then energy stored by the spring is (if T is the tension in spring and k is spring constant)
Options
- AT^2 2 k
- BT^2 2 k^2
- C2 k T^2
- D2 T^2 k
Correct answer
A. T^2 2 k
Step-by-step solution
The energy stored in the spring is E= 1 2 k x^2 (i) and expansion in the spring is x= T k (ii) From equations (i) and (ii), we get E= 1 2 k T^2 k^2 = 1 2 T^2 k = T^2 2 k