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NEET
Exam
NEET
Subject
Physics
Chapter
Alternating Current

NEET · Physics · Alternating Current

In an LCR series circuit, if the angular frequency is gradually in...

In an LCR series circuit, if the angular frequency is gradually in creased then match the following columns (
(A) (C) (D)
Column-IColumn-II
Capacitive reactance(i)Will continuously increase
(B)Inductive reactance(ii)Will remain constant
Resistance(iii)<td>Willfirstdecreaseandthen</td></tr><tr><td></td>increase<td>\begin{array}{l}<td> Will first decrease and then</td></tr><tr><td></td> increase <td>\end{array}
Total impedance(iv)Will continuously decrease
)

Options

  1. A(A)−(iv),(B)−(i),(C)−(ii),(D)−(iii)(\mathrm{A})-(\mathrm{iv}),(\mathrm{B})-(\mathrm{i}),(\mathrm{C})-(\mathrm{ii}),(\mathrm{D})-(\mathrm{iii})
  2. B(A) - (i), (B) - (iii), (C) - (iv), (D) - (ii)
  3. C(A)−(ii),(B)−(iii),(C)−(i),(D)−(iv)(\mathrm{A})-(\mathrm{ii}),(\mathrm{B})-(\mathrm{iii}),(\mathrm{C})-(\mathrm{i}),(\mathrm{D})-(\mathrm{iv})
  4. D(A)−(i),(B)−(iv),(C)−(ii),(D)−(iii)(A)-(i),(B)-(i v),(C)-(i i),(D)-(i i i)

Correct answer

A. (A)−(iv),(B)−(i),(C)−(ii),(D)−(iii)(\mathrm{A})-(\mathrm{iv}),(\mathrm{B})-(\mathrm{i}),(\mathrm{C})-(\mathrm{ii}),(\mathrm{D})-(\mathrm{iii})

Step-by-step solution

XC=1ωC, so XC∝1ω∴(A)−(iv)XL=ωL, so XL∝ω∴(B)−(i)\begin{aligned} & \mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}, \text{ so } \mathrm{X}_{\mathrm{C}} \propto \frac{1}{\omega} \\ & \therefore(\mathrm{A})-(\mathrm{iv}) \\ & \mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}, \text{ so } \mathrm{X}_{\mathrm{L}} \propto \omega \\ & \therefore(\mathrm{B})-(\mathrm{i})\end{aligned} And R\mathrm{R} is not a function of ω∴(C)−(ii)\omega \therefore(\mathrm{C})-(\mathrm{ii}) Impedence Z\mathrm{Z} is the minimum at resonance frequency. ∴(D)−(iii)\therefore(\mathrm{D})-(\mathrm{iii})
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