Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEETPhysicsAlternating Current

Match List - I with List - II. List-I List-II (A) AC generator (I) Detects the presence of current in the circuit (B) Galvanometer (II) Converts mechanical energy into electrical energy (C) Transformer (III) Works on the principle of resonance in AC circuit (D) Metal detector (IV) Changes an alternating voltage for smaller or greater value

Options

  1. AA - II , B - I , C - IV , D - III
  2. BA - II , B - I , C - III , D - IV
  3. CA - III , B - IV , C - II , D - I
  4. DA - III , B - I , C - II , D - IV

Correct answer

A. A - II , B - I , C - IV , D - III

Step-by-step solution

AC generator-- Converts mechanical energy into electrical energy. A → I I . Galvanometer-- Detects the presence of current in the circuit B - I . Transformer-- Changes an alternating voltage for smaller or greater value C - I V . Metal detector-- Works on the principle of resonance in AC circuit D - I I I .

Practice Alternating Current on Quantrex Academy →

More from Alternating Current

A step down transformer connected to an a.c. mains of 220 V is made to operate at 5.5 V, 44 W lamp. The current in the primary circuit is (Ignore power losses) 2026Which phasor diagram represents LCR circuit at resonance? 2026For an R-L series circuit, the power factor is 3 2 , for R-L frequency f Hz. If the frequency doubles, the new power factor will be 2026In an AC circuit, the current is I = 100 (5t) A. The value of I_ rms is 2026The ratio of power factor of purely resistive circuit to purely reactive circuit is ( 0^ = 1 and 90^ = 0 ) 2026In an LCR series circuit, at resonance, 2026In an AC circuit, E and I are given by E = 150 (150t) V and I = 150 (150t + 3 ) A. The power dissipated in the circuit is (60)^ = 1/2 2026A series LCR circuit is connected across a source E of e.m.f. E=15 (50 t- 3 ) . The current from the supply is I=5 (50 t+ 6 ) . The impedance of the circuit and the phase differenc 2026 Full Alternating Current list All NEET PYQs