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A graph is plotted showing the kinetic energy ( K ) of an electron on the y-axis versus the reciprocal of its orbital radius ( 1 r ) on the x-axis. Which of the following statements correctly describes the shape of the graphs and their relative slopes for a Hydrogen atom (H) and a singly ionized Helium ion (He ^+ )?

Options

  1. AThe graphs are parabolas, because kinetic energy depends on the square of the velocity.
  2. BThe graphs are straight lines passing through the origin, and the slope for He ^+ is twice the slope for H.
  3. CThe graphs are straight lines passing through the origin, and the slope for He ^+ is four times the slope for
  4. DThe graphs are straight lines passing through the origin, and the slope for He ^+ is half the slope for H.

Correct answer

B. The graphs are straight lines passing through the origin, and the slope for He ^+ is twice the slope for H.

Step-by-step solution

The electrostatic force between the nucleus (charge Ze ) and the electron (charge e ) provides the centripetal force: mv^2 r = 1 4 ₀ Ze^2 r^2 Multiplying both sides by r , we get: mv^2 = 1 4 ₀ Ze^2 r The kinetic energy K of the electron is: K = 1 2 mv^2 = 1 8 ₀ Ze^2 r This can be written as: K = ( Ze^2 8 ₀ ) 1 r This is a linear equation of the form y = mx , where y = K and x = 1 r . Thus, the graph of K versus 1 r is a straight line passing through the origin. The slope of the graph is m = Ze^2 8 ₀ , which is dire

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