The electrostatic potential energy of an electron in a Bohr orbit is -3.02 eV . Its kinetic energy and total energy are, respectively,

Step-by-step solution

For an electron in a hydrogen-like atom, the potential energy (PE), kinetic energy (KE), and total energy (TE) are related by: TE = PE 2 and KE = - TE Given PE = -3.02 eV , TE = -3.02 2 = -1.51 eV KE = -(-1.51) = 1.51 eV Therefore, the kinetic and total energies are 1.51 eV and -1.51 eV , respectively. Answer: 1.51 eV , ,-1.51 eV