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NEET
Exam
NEET
Subject
Physics
Chapter
Nuclear Physics

NEET · Physics · Nuclear Physics

Radioactive element decays to form a stable nuclide, then the rate...

Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown byRadioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown byRadioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown byRadioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown byRadioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown byRadioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown byRadioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by

Options

  1. AWhich one of the following is correct in respect of the function f(x)=x x+ x+(1)/(2) ^2 x ?
  2. BWhich one of the following is correct in respect of the function f(x)=x x+ x+(1)/(2) ^2 x ?
  3. CWhich one of the following is correct in respect of the function f(x)=x x+ x+(1)/(2) ^2 x ?
  4. DWhich one of the following is correct in respect of the function f(x)=x x+ x+(1)/(2) ^2 x ?

Correct answer

C. Which one of the following is correct in respect of the function f(x)=x x+ x+(1)/(2) ^2 x ?

Step-by-step solution

No. of nuclide at time t\mathrm{t} is given by
\\ N=No\mathrme−λt\mathrm{N}=\mathrm{N}_{\mathrm{o}} \mathrme^{-\lambda \mathrm{t}}\\ \\ Where, No=\mathrm{N}_{\mathrm{o}}= initial nuclide \\ Thus this equation is equivalent to y=ae−kx\mathrm{y}=\mathrm{ae}^{-\mathrm{kx}}
So correct graph is in option (c)
Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is shown by
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