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NEET
Exam
NEET
Subject
Physics
Chapter
Nuclear Physics

NEET · Physics · Nuclear Physics

Deuteron is a bound state of a neutron and a proton with a binding...

Deuteron is a bound state of a neutron and a proton with a binding energy B = 2.2 MeV. A γ -ray of energy E is aimed at a deuteron nucleus to try to break it into a (neutron + proton) such that the n and p move in the direction of the incident γ-ray. If E = B, show that this cannot happen. Hence calculate how much bigger than B must E be for such a process to happen

Options

  1. AB2mc2\frac{{{B}^{2}}}{m{{c}^{2}}}
  2. BB22mc2\frac{{{B}^{2}}}{2m{{c}^{2}}}
  3. CB24mc2\frac{{{B}^{2}}}{4m{{c}^{2}}}
  4. D3B24mc2\frac{3{{B}^{2}}}{4m{{c}^{2}}}

Correct answer

C. B24mc2\frac{{{B}^{2}}}{4m{{c}^{2}}}

Step-by-step solution

Correct Option is : (C)
B24mc2\frac{{{B}^{2}}}{4m{{c}^{2}}}
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