In a certain nuclear event, the total energy released is 9 × 10^ 13 J . The equivalent mass destroyed to produce this energy is:

Question

Quantrex Academy · Accepted Answer

Correct answer: B. 1 g

From the mass-energy equivalence principle, the energy released is given by

E = mc^2

.

Rearranging for mass

m

:

m = \dfrac{E}{c^2}

Given

E = 9 \times 10^{13} \text{ J}

and the speed of light

c = 3 \times 10^8 \text{ m/s}

:

m = \dfrac{9 \times 10^{13}}{(3 \times 10^8)^2}

m = \dfrac{9 \times 10^{13}}{9 \times 10^{16}}

m = 10^{-3} \text{ kg}

Converting kilograms to grams:

m = 10^{-3} \times 10^3 \text{ g} = 1 \text{ g}

Answer:

1 \text{ g}

In a certain nuclear event, the total energy released is 9 × 10^ 13...