Calculate power output of ( ₉₂²³⁵ U ) reactor, if it takes 30 days to use up (2 ~kg ) of fuel, and if each fission gives (185 ~MeV ) of useable energy. Avogadro's number (=6 10²³ / mol ) ?

Step-by-step solution

Mass of ( ₉₂²³⁵ U ) per second in the reactor is (m= 2 10^3 30 24 60 60 =7.72 10⁻⁴ ~g / sec ) ( ) Number of fissions reaction per second ( aligned & = 6 10²³ 235 m= 6 10²³ 7.72 10⁻⁴ 235 & =1.97 10¹⁸ / sec aligned ) Power of nuclear reactor (=1.97 10¹⁸ 185 MeV / s ) (=1.97 10¹⁸ 185 10^6 1.6 10⁻¹⁹ ~J / s ). (=58.3 ~MW ).