NEET2006PhysicsNuclear PhysicsActual
₉₂²³⁸ U has 92 protons and 238 nucleons. It decays by emitting an alpha particle and becomes
Options
- A₉₂²³⁴ U
- B₉₀²³⁴ Th
- C235 U
- D₉₃²³⁷ ~Np .
Correct answer
B. ₉₀²³⁴ Th
Step-by-step solution
Emission of alpha particle, decrease the mass number by 4 and charge number by 2 . Decrease in mass number =238-4=234 Decrease in charge number =92-2=90 ₉₀²³⁴ Th is emitted.