Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEET2006PhysicsNuclear PhysicsActual

The fossil bone has a ¹⁴ C : ¹² C ratio, which is [1 / 16] of that in a living animal bone. If the halflife time of ¹⁴ C is 5730 years, then the age of the fossil bone is

Options

  1. A11460 years
  2. B17190 years
  3. C22920 years
  4. D45840 years.

Correct answer

C. 22920 years

Step-by-step solution

After 5730 years, the number of C ¹⁴ remaining is 1 2 th original. To have (1 / 16) original value, it takes (1 / 2)^4, 4 half lives. Therefore, the bone is 4 5730 years =22920 years old.

Practice Nuclear Physics on Quantrex Academy →

More from Nuclear Physics

Consider the following nuclear fission reaction ₀^1 n + ₉₂²³⁵U _Z^A Y + ₄₁⁹⁹Nb + neutrons . If 4 neutrons are released during the fission process, then A and Z are 2026Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂ respectively. The ratio R₁ R₂ is 2026At time t = 0 , the activity of a radioactive substance is 1600 Bq. At t= 8 s, the activity remains 100 Bq. The activity at t = 2 s, the is 2026A radioactive nucleus ₉₂X²³⁵ decays to ₉₁Y²³¹ . Which of the following particles are emitted? 2026In a given reaction, ^ A _ Z X ^ A _ Z+1 Y ^ A-4 _ Z-1 K ^ A-4 _ Z-1 K the radioactive radiations are emitted in the sequence of 2026When a nucleus in an atom undergoes a radioactive decay, the atomic number and/or mass number of the atom 2026A common example of ^- decay is ₁₅ P ³² ₁₆ S ³² + x + y Then x and y , respectively, stand for 2026For a radioactive nucleus that undergoes ^+ decay, which of the following CANNOT occur? 2026 Full Nuclear Physics list All NEET PYQs