A radioactive substance decays to 1 / 16^ th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is

Step-by-step solution

We know that the activity of radioactive substance, A=A₀ e^ - t aligned & A A₀ =e^ - t =e^ - 0.693 T^ 1 / 2 t [ T_ 1 / 2 = 0.693 ] & 1 16 =e^ - 0.693 40 T^ 1 / 2 0.693 40 T_ 1 / 2 = 16 & T_ 1 / 2 = 0.693 40 16 =9.997 10 days. aligned