An atomic power nuclear reactor can deliver 300 MW. The energy released due to fission of each nucleus of uranium atoms U ²³⁸ is 170 MeV . The number of uranium atoms fissioned per hour will be

Step-by-step solution

Power = Energy Time =300 10^6 ~W =3 10^8 ~J / s Energy released due to fission gathered =170 MeV =170 10^6 1.6 10⁻¹⁹ =27.2 10⁻¹² ~J gathered Number of atoms fissioned per second = 3 10^8 27.2 10⁻¹² = 3 10²⁰ 27.2 Number of atoms fissioned per hour aligned & = 3 10²⁰ 3600 27.2 & = 3 36 27.2 10²²=4 10²² ~m aligned