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NEET2016PhysicsNuclear PhysicsActual

A ^7 Li target is bombarded with a proton beam current of 10⁻⁴ ~A for one hour to produce ^7 Be of activity 1.8 10^8 disintegrations per second. Assuming that one ^7 Be radioactive nuclei is produced by bombarding 1000 protons, its half-life is

Options

  1. A0.87 10^7 ~s
  2. B0.2 10^7 ~s
  3. C0.67 10^8 ~s
  4. D0.87 10^6 ~s

Correct answer

A. 0.87 10^7 ~s

Step-by-step solution

Given, i=10⁻⁴ ~A , t=1 ~h =3600 ~s We know that, q= it =10⁻⁴ 1 3600=0.36 C Number of protons = q e = 0.36 1.6 10⁻¹⁹ [ e=1.6 10⁻¹⁹ C ]=2.25 10^8 Number of ^7 Be nuclei produced = 2.25 10¹⁸ 1000 =2.25 10¹⁵ Activity of ^7 Be =1.8 10^8 disintegration / s aligned Activity, A & = N & = 2 t_ 1 / 2 N aligned [ = 2 t_ 1 / 2 ]1.8 10^8= 0.693 t_ 1 / 2 2.25 10¹⁵ t_ 1 / 2 = 0.693 2.25 10¹⁵ 1.8 10^8 =0.87 10^7 ~s

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