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A radioactive element ₉₀ X²³⁸ decays into ₈₃ Y²²² . The number of -particles emitted are

Options

  1. A1
  2. B2
  3. C4
  4. D6

Correct answer

A. 1

Step-by-step solution

-particles are emitted = 238-222 4 =4 The atomic number is decreased 90-4 2=82 As atomic number of ₈₃ Y²²² , So, atomic number is increased by 1 , therefore, one -particle is emitted.

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