Graph shows the variation of de-Broglie wavelength $\lambda$ versus $\frac{1}{\sqrt{V}}$ where $V$ is the accelerating potential for four particles, P, Q, R, S carrying same charge but of mass $m_1, m_2, m_3, m_4$ . Which one represents a particle of smaller mass?

Question

Graph shows the variation of de-Broglie wavelength

\lambda

versus

\frac{1}{\sqrt{V}}

where

V

is the accelerating potential for four particles, P, Q, R, S carrying same charge but of mass

m_1, m_2, m_3, m_4

. Which one represents a particle of smaller mass? Graph shows the variation of de-Broglie wavelength λ versus 1 V where V is the accelerating potential for four

Graph shows the variation of de-Broglie wavelength λ versus 1 V where V is the accelerating potential for four

Quantrex Academy · Accepted Answer

Correct answer: A. m_4

De-broglie wavelength, λ=(h)/(p) Kinetic energy : aligned & K=(p^2)/(2 m)=q V & λ= h 2 m q V aligned Slope of straight line θ= h 2 m q Hence, more is slope of line, less is the mass.

Graph shows the variation of de-Broglie wavelength λ versus 1 V...

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