NEETPhysicsDual Nature of Matter
Graph shows the variation of de-Broglie wavelength ( ) versus 1 V where ' V ' is the accelerating potential for four particles A, B, C, D carrying same charge but of masses m ₁, ~m ₂ , m ₃, ~m ₄ . Which on represents a particle of largest mass?
Options
- Am ₁
- Bm ₂
- Cm ₃
- Dm ₄
Correct answer
A. m ₁
Step-by-step solution
de Broglie wayelength = h p = h 2 mqv v = h 2 mq ( 1 v ) = 1 2 mq Slope of the graph = 1 2 mq The slope will be maximum for minimum mass. m ₄ is minimum and m ₁ will be minimum.