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Decomposition of ( N ₂ O ₄( ~g ) ) takes place as follows: ( N ₂ O ₄( ~g ) 2 NO ₂( ~g ) ) ' (D ) ' is the vapour density at initial stage and ' (d ) ' is the vapour density at equilibrium. We get following graph when the degree of dissociation ' ( ) ' is plotted against ( (D / d ) ) What is the value of ( D d ) at A ?

Options

  1. A0
  2. B0.5
  3. C1
  4. D1.5

Correct answer

C. 1

Step-by-step solution

For ( N ₂ O ₄ 2 NO ₂ ), the relation is ( D d =1+ ) At point A, ( =0 ), so ( D d =1 )

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