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NEET 2025
Exam
NEET
Year
2025
Subject
Chemistry
Chapter
Chemical Equilibrium

NEET 2025 · Chemistry · Chemical Equilibrium

For the reaction A(g) leftharpoons 2 ~B(~g) , the backward reaction...

For the reaction A(g)⇌2 B( g)\mathrm{A}(\mathrm{g}) \rightleftharpoons 2 \mathrm{~B}(\mathrm{~g}), the backward reaction rate constant is higher than the forward reaction rate constant by a factor of 2500 , at 1000 K . [Given : R=0.0831 L atm mol−1 K−1\mathrm{R}=0.0831 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} ] Kp\mathrm{K}_{\mathrm{p}} for the reaction at 1000 K is

Options

  1. A83.1
  2. B2.077×1052.077 \times 10^5
  3. C0.033
  4. D0.021

Correct answer

C. 0.033

Step-by-step solution

KC=KfKb=Kf2500 Kf=12500 Kp=KC(RT)Δng=12500(0.0831×1000)1 Kp=0.033\begin{aligned} \mathrm{K}_{\mathrm{C}} & =\frac{\mathrm{K}_{\mathrm{f}}}{\mathrm{K}_{\mathrm{b}}} \\ & =\frac{\mathrm{K}_{\mathrm{f}}}{2500 \mathrm{~K}_{\mathrm{f}}} \\ & =\frac{1}{2500} \\ \mathrm{~K}_{\mathrm{p}} & =\mathrm{K}_{\mathrm{C}}(\mathrm{RT})^{\Delta \mathrm{n}_{\mathrm{g}}} \\ = & \frac{1}{2500}(0.0831 \times 1000)^1 \\ \mathrm{~K}_{\mathrm{p}} & =0.033\end{aligned}
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