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For the dissociation of ( PCl _ 5( ~g ) ), the variation of ((1+ ) ) against ( ( D d ) ) is represented as.

Correct answer

0

Step-by-step solution

( Let the degree of dissociation = . ) - Initial moles = 1 - At equilibrium: - (P C l₅=1- ) - ( PCl ₃= ) - (C l₂= ) So, total moles (=1+ ). Average molar mass: (M= M_ P C l₅ 1+ ) Vapour density at equilibrium: (d= M 2 = D 1+ , where D= M_ P C l₅ 2 ) Thus: ( D d =1+ ) Hence, ( (1+ ) ) vs ( D d ) is a straight line through origin.

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